Oxygen

and a temperature of 287 K. The tanks are stored in a separate room, and the oxygen is pumped to the patient’s room, where it is administered at a pressure of 1.00 atmosphere and a temperature of 297 K. What volume does 1.00 m3 of oxygen in the tanks occupy at the conditions in the patient’s room?

PV=nRT and PV=NkT I do not know which formula to use and how to apply it.

Amount of stuff (n) being equal,
those equations tell you that:
V is proportional to T/P

So take your original volume and multiply by the ratio of new to old temps and divide by the ratio of new to old pressures.

New Volume
= Old Volume * (New temp/Old temp) / (New pressure / old pressure)

They give you all that stuff. Plug and chug.

2 Responses

1. Bekki B Says:
   May 13th, 2010 at 5:47 am

   Amount of stuff (n) being equal,
   those equations tell you that:
   V is proportional to T/P

   So take your original volume and multiply by the ratio of new to old temps and divide by the ratio of new to old pressures.

   New Volume
   = Old Volume * (New temp/Old temp) / (New pressure / old pressure)

   They give you all that stuff. Plug and chug.
   References :

2. Scarlet Says:
   May 13th, 2010 at 6:13 am

   Use PV=nRT. The amount of oxygen is constant, so n is constant. Thus you get n = pv/(Rt) = PV/(RT). The lowercase letters signify the first set of conditions and the uppercase letters signify the second set of conditions.

   p=70 atm, v=1 cubic meter, t=287 K

   P=1 atm , T= 287K, and V is unknown.

   R is the gas constant 0.0821 L x atm / (K x mol) You will have to convert the volume in liters to use the ideal gas law.
   References :

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